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sci.physics.relativity |
Dirk Van de moortel wrote: > Observer I can parametrize the worldline of A with the same > Since v(T+dT) is the standard SR composition ('addition') of the > To calculate dv(T)/dT we use > Rearrange: > Inverting to > Use the standard SR Lorentz transformation (with c=1) between > Integrate beteen 0 and T: > If possible, eliminate T to find the equation of the worldline x(t) > If possible, invert the expression for t(T) to find the proper time > Summary: > Example: > Eliminate T: > Also proper time as a function of coordinate time: > Re-introduce c and we find: Thanks
> Suppose I is an inertial observer and A is an arbitrarily accelerated http://hermes.physics.adelaide.edu.au/~dkoks/Faq/Relativity/SR/rocket...
> observer that constantly monitors the acceleration he feels as a
> function a(T) of his own proper time T (this is 'tau').
> At each time T, observer A can write the amount with which his
> velocity has changed during a small (infinitesimal) proper time
> interval dT during which the acceleration does not change as
> dV(T) = a(T) dT
> This change of velocity is to be regarded with respect to the
> instantaneously comoving inertial frame at time T.
> proper time T, so he will see infinitesimally consecutive velocities
> of A as v(T) and v(T+dT).
> velocities v(T) and dV(T), we can write (using c=1):
> v(T+dT) = [ v(T) + dV(T) ] / [ 1 + v(T) dV(T) ]
> which, using the expression for dV(T), becomes:
> v(T+dT) = [ v(T) + a(T) dT ] / [ 1 + v(T) a(T) dT ]
> [ v(T+dT) - v(T) ] / dT = a(T) [1-v^2(T)] / [ 1 + v(T) a(T) dT ]
> Take the limit dT --> 0
> dv(T)/dT = a(T) [ 1 - v^2(T) ]
> dv(T) / [ 1 - v^2(T) ] = a(T) dT
> Integrating between 0 and T
> argtanh(v(T)) - argtanh(v(0)) = Int{ 0 to T; a(T') dT' }
> and using the abbreviation
> A(T) = Int{ 0 to T; a(T') dT' },
> we get
> argtanh(v(T)) - argtanh(v(0)) = A(T)
> [ v(T) - v(0) ] / [ 1 - v(T) v(0) ] = tanh(A(T))
> and isolating v(T) gives:
> v(T) = [ v(0) + tanh(A(T)) ] / [ 1 + v(0) tanh(A(T)) ]
> or simply, if v(0) = 0:
> v(T) = tanh(A(T))
> the frame I and the instantaneously comoving inertial frame of A
> at time T:
> dt = gamma(T) ( dT + v(T) dX )
> dx = gamma(T) ( dX + v(T) dT )
> Since we are working on the worldline of I where X=0 and thus
> dX=0, we get:
> dt/dT = gamma(T)
> = 1 / sqrt( 1-v^2(T) )
> = 1 / sqrt( 1-tanh^2(A(T)) )
> = cosh(A(T))
> and
> dx/dT = gamma(T) * v(T)
> = v(T) / sqrt( 1-v^2(T) )
> = tanh(A(T)) / sqrt( 1-tanh^2(A(T)) )
> = sinh(A(T))
> x(T) = Int{ 0 to T; sinh(A(T')) dT' }
> t(T) = Int{ 0 to T; cosh(A(T')) dT' }
> of the accelerated observer A in the frame of the intertial
> observer I:
> x(t) = ...
> of A as a function of the coordinate time t of I:
> T(t) = ...
> and use it to find the velocity v(t) as a function of coordinate time t:
> v(t) = tanh(A(T(t)))
> ========
> x and t = coordinates of object as seen by inertial frame.
> a(T) = felt proper acceleration as function of proper time T.
> A(T) = Int{ 0 to T; a(T') dT' }
> v(T) = tanh(A(T)) if v(0) = 0
> dt/dT = cosh(A(T))
> dx/dT = sinh(A(T))
> x(T) = Int{ 0 to T; sinh(A(T')) dT' }
> t(T) = Int{ 0 to T; cosh(A(T')) dT' }
> eliminate T to find worldline equation x(t)
> ========
> The rocket with constant acceleration of the FAQ:
> Take Nice to see the full details Dirk But at a logical level all you really
> a(T) = a = contant
> So
> A(T) = Int{ 0 to T; a(T') dT' }
> = a T
> So
> v(T) = tanh(A(T))
> = tanh(a T)
> and
> x(T) = Int{ 0 to T; sinh(a T') dT' }
> = 1/a * ( cosh(a T) - 1 )
> and
> t(T) = Int{ 0 to T; cosh(A(T')) dT' }
> = 1/a * sinh(a T)
> (x+1/a)^2 - t^2 = 1/a^2
> giving the hyperbola
> x(t) = 1/a [ sqrt( 1 + (a t)^2 ) - 1 ]
> T(t) = 1/a * argsinh(a t)
> so
> v(t) = tanh( a T(t) )
> = tanh( argsinh(a t) )
> = a t / sqrt[ 1 + (a t)^2 ]
> v(T) = c tanh(aT/c)
> x(T) = c^2/a [ cosh(aT/c) - 1 ]
> t(T) = c/a sinh(aT/c)
> gamma(T) = cosh(aT/c)
> and as functions of t:
> T(t) = c/a argsinh(at/c)
> and
> x(t) = c^2/a sqrt( 1 + (at/c)^2 ) (the hyperbola)
> v(t) = at / sqrt( 1 + (at/c)^2 )
> gamma(t) = sqrt( 1 + (at/c)^2 )
> which are the equations of the FAQ entry.
need to remember is that during an infinitesimal time period an accelerated
system can be considered to be traveling and constant velocity so SR
applies.
Bill