Newsgroups: comp.soft-sys.math.mathematica
From: Jean-Marc Gulliet <jeanmarc.gull...@gmail.com>
Date: Sat, 4 Aug 2007 09:48:22 +0000 (UTC)
Local: Sat 4 Aug 2007 10:48
Subject: Re: Integration with non-numeric parameters
(*snip*)
> But when I try (*snip*) > q=Exp[-(x1-t)^2/2*sigma^2*t] > Integrate[q, {t, .5,1}] > Now Mathematica does not solve this integral, it just repeats the > I am trying to get an expression in terms of x1. Why do I get a It is conventional (by design) that Mathematica returns an expression For instance, having started a new Mathematica session, if we try to In[1]:= f[2] Out[1]= f[2] Now, we give a definition (a meaning) to the symbol f. In[2]:= f[x_] = 2 x Out[2]= 2 x From now on, evaluating f will return a value. In[3]:= f[2] Out[3]= 4 Of course, *Integrate* is a built-in function that has already a For instance, Mathematica knows how to integrate E^(-x^2) (in terms of In[1]:= Integrate[Exp[-x^2], x] Out[1]= 1/2 Sqrt[\[Pi]] Erf[x] In[2]:= Integrate[Exp[-x^3], x] Out[2]= -((x Gamma[1/3, x^3])/(3 (x^3)^(1/3))) In[3]:= Integrate[Exp[-x^3 - x^2], x] Out[3]= Integrate[E^(-x^2 - x^3), x] Regards, You must Sign in before you can post messages.
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