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comp.soft-sys.math.mathematica |
On 3 , 13:51, ingramfina...@gmail.com wrote: > Integrate[y, {t, .5, 1}] > I get the following answer: > (0.34657*x1/sigma^2) > OK, so far, so good. It appears that I can generate an answer with a > But when I try > q=Exp[-(x1-t)^2/2*sigma^2*t] > Integrate[q, {t, .5,1}] > Now Mathematica does not solve this integral, it just repeats the > I am trying to get an expression in terms of x1. Why do I get a > Any help you can give me is much appreciated! So, In[43]:= In[44]:= Out[44]= In[45]:= Out[45]= In[46]:= Out[46]= In[47]:= Out[47]= The latter integral is not a trivial one! In another CAS, convert("Integrate[E^((-(1/2))*sigma^2*t*(-t + x1)^2), {t, 1/2, 1 Again the integral is stated unevaluated. Dimitris
> When I use Mathematica to solve the following Do not mix arbitrary precision numbers with symbolic built in
> y=x1/(2*sigma^2*t)
> non-numeric parameter. Note that I am looking for an answer in terms
> of x1.
> command
> statement like this instead of an answer? There is something about
> the functional form of the integrand that is causing the problem, I
> just don't know what it is.
functions.
Use 1/2 instead of 0.5!
Clear["Global`*"]
y = x1/(2*sigma^2*t)
x1/(2*sigma^2*t)
Integrate[y, {t, 1/2, 1}]
(x1*Log[2])/(2*sigma^2)
q = Exp[(-((x1 - t)^2/2))*sigma^2*t]
E^((-(1/2))*sigma^2*t*(-t + x1)^2)
Integrate[q, {t, 1/2, 1}]
Integrate[E^((-(1/2))*sigma^2*t*(-t + x1)^2), {t, 1/2, 1}]
1}]",FromMma,evaluate);
/ 2 2
| sigma t (-t + x1)
| exp(- -------------------) dt
| 2
/
1/2